Viswanathan Anand draws with Fabiano Caruana in Zurich Chess Challenge

Zadar (Croatia), Jun 22: Grigor Dimitrov took to Instagram to announce that he has tested positive for coronavirus. The tennis star was one of the players who took part in the Adria Tour with the likes Novak Djokovic, Alexander Zverev and Dominic Thiem among others.

Taking to Instagram, the player wrote: "Hi Everyone-I want to reach out and let my fans and friends know that I tested positive back in Monaco for Covid-19. I want to make sure anyone who has been in contact with me during these past days gets tested and takes the necessary precautions. I am so sorry for any harm I might have caused. I am back home now and recovering. Thanks for your support and please stay safe and healthy."

He also urged those who had come in contact with him over the last few days in Monaco should also get tested for the deadly virus.

Meanwhile, World no.1 Djokovic reached the final of his exhibition tournament in Zadar, Croatia, after easing through the round-robin group stage on the first day. This is the second stage of the Adria Tour with Austrian Dominic Thiem winning the first leg in Belgrade, Serbia.

Djokovic started by saving three set points in his 4-3, 4-1 win over fellow Serb Pedja Krstin. He then beat home favourite Borna Coric 4-1, 4-3 in front of several thousand fans at the Visnjik tennis complex.

The tournament in Zadar is being played on red clay over two days. In the other group, Russian Andrey Rublev is in pole position to advance into the final after wins over 2014 US Open champion Marin Cilic and Serb Danilo Petrovic. He faces German star Alexander Zverev in the final round robin match on Sunday who stayed in contention after beating Cilic 4-3, 0-4, 4-3.

Djokovic''s own inconsequential final group match is against Croatian Dino Serdarusic who replaced Grigor Dimitrov after the Bulgarian pulled out of the tournament with sickness following his opening 4-1, 4-1 loss to Coric.

Rajkot, Jan 16: Skipper Virat Kohli is set to be back at his regular number three position after the strategy of coming two-down boomeranged in the lung-opener as India take on a resolute Australia in the must-win second ODI here on Friday.

India go into the game 0-1 down after Australia registered a 10-wicket win in the lung-opener at Mumbai, courtesy David Warner and Aaron Finch, who hit unbeaten hundreds.

In a bid to field all three in-form players -- Rohit Sharma, Shikhar Dhawan and KL Rahul --, Kohli dropped himself down the order but the plan backfired spectacularly as he was unable to convert his start.

Opener Dhawan later said he was ready to bat at number three if asked to by the team management, but since Kohli has been successful at that position, the skipper would be more than willing to walk in one-down.

Kohli batting at three also provides stability to the middle-order.

With a concussed Rishabh Pant out of the second game, Rahul is a certainty as he will keep wickets.

So, like in the last game, Rohit and Dhawan, who made a dogged 74 off 91 balls in Wankhede, could open, and there could be a toss-up between Rahul and young Shreyas Iyer at number four. Iyer had a rare failure on Tuesday.

Pant's absence could pave the way for the inclusion of Karnataka batsman Manish Pandey, who made optimum use of the opportunity that he got in the third T20 against Sri Lanka in Pune.

It would also be interesting to see which among the experienced Kedar Jadhav and rookie Shivam Dube makes the squad.

Rohit, who had a phenomenal 2019, failed in the first game, but given the form he is in, the opener is expected to bounce back strongly here.

Ditto for Kohli, who is just one hundred short of equalling cricket icon Sachin Tendulkar's record of most hundreds on home soil for India.

The bowlers led by Jasprit Bumrah had a forgettable outing at the Wankhede and they would be more than eager to make a strong comeback and prove their mettle.

Bumrah, since his comeback, has not been as effective as earlier and he would like to change the perception.

It would be interesting to see whether India play Delhi speedster Navdeep Saini or persist with Shardul Thakur, who gave away 43 runs in Mumbai.

Ravindra Jadeja looks a certainty and so the choice would be between chinaman Kuldeep Yadav, who conceded 55 runs in the first ODI and Yuzvendra Chahal as the lead spinner.

On the other hand, a high on confidence Australia will be looking to seal the issue to register back to back series wins in India, a rare feat for any visiting team. The Finch-Warner combination will look forward to carry the momentum.

Their middle-order comprising the experienced Steve Smith, in-form Marnus Labuschange, Ashton Turner and Alex Carey looks more or less settled.

If all of them fire in unison, along with the openers, then it will hard for the opposition bowlers.

However, it will be quite a test of their middle-order at the Saurashtra Cricket Association stadium.

Australian bowlers also showed at the Wankhede, why they are considered among the best.

Led by pace spearhead Mitchell Starc, they bundled out India for a sub-par 255 and Mitchell Starc and Pat Cummins would be raring to go once again.

Spinners Adam Zampa and Ashton Agar, not only contained the runs, but provided crucial breakthroughs and are expected to play a similar role again in the middle overs.

The track here is expected to be a belter and India can draw confidence from the home series against New Zealand in 2017, when they won 2-1 after losing the opener, co-incidentally in Mumbai.

Squads:

India: Virat Kohli (Captain), Rohit Sharma, Shikhar Dhawan, K L Rahul (wicketkeeper), Shreyas Iyer, Manish Pandey, Kedar Jadhav, Shivam Dube, Ravindra Jadeja, Yuzvendra Chahal, Kuldeep Yadav, Navdeep Saini, Jasprit Bumrah, Shardul Thakur and Mohammed Shami.

Australia: Aaron Finch (Captain), Alex Carey (Wicket-keeper), Patrick Cummins, Sean Abbott, Ashton Agar, Peter Handscomb, Josh Hazlewood, Marnus Labuschange, Kane Richardson, Steve Smith, Mitchell Starc, Ashton Turner, David Warner and Adam Zampa.

Match starts at 1.30.

New Delhi, Feb 20: Grappler Divya Kakran on Thursday became the second Indian woman to win a gold medal at the ongoing Asian Wrestling Championship.

Divya, a bronze medallist at Asian Games 2018, earned her first gold by winning all her four bouts against Kazakhstan, Mongolia, Uzbekistan and Japan.

Her final bout against Naruha Matsuyuki of Japan was the closest one but she managed to outclass her opponent 6-4 to seal her name on the gold medal. The 68 kg category was played in round-robin format as only five wrestlers were in the fray.

India is likely to add some more medals to its tally when Nirmala Devi, Pinki, and Sarita go out to grapple for the yellow metal in their respective weight categories.

Three-time Commonwealth championship gold medallist, Nirmala Devi (50 kg) first defeated Munkhnar Byambasuren of Mongolia in the quarterfinals by 6-4 to reach the semis.

In the semi-finals, Nirmala got the better of Dauletbike Yakhshimuratova of Uzbekistan by 10-0 and will play against 2018 Under-23 World Champion Miho Igarashi of Japan for the gold medal.

Pinki (55 kg) started her day on a winning note against Shokhida Akhmedova of Uzbekistan by 12-4 in round 3 and lost to Kana Higashikawa of Japan to enter the semis where she defeated Marina Zuyeva of Kazakistan by a score of 6-0.

Pinki will play in the gold medal bout against Dulguun Bolormaa of Mongolia.

Sarita (59 kg) will now face Battsetseg Altantsetseg of Mongolia in the gold medal bout after winning against her opponents in the qualifiers, quarterfinals and semi-final by a score of 10-0, 11-0 and 10-3, respectively.